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A radio wave transmits 36.8 W/m2 of power per unit area. A flat surface of area A is perpendicular to the direction of propagation of the wave. Assuming the surface is a perfect absorber, calculate the radiation pressure on it.

Respuesta :

Manetho

Answer:

122.6 nPa

Explanation:

Here ,

Intensity of incident light , I = 36.8 W/m^2

angle with area, θ = 0 degree

for a perfect absorber ,

radiation pressure = [tex]\frac{Icos\theta}{c}[/tex]

I=  Intensity of incident light, c= speed of light

radiation pressure =  [tex]\frac{36.8\times cos0}{3\times10^8}[/tex]

radiation pressure = 12.26×10^-8 Pa

radiation pressure = 122.6 nPa

the radiation pressure acting on the 122.6 nPa

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