Answer:
There is a constant emf induced in the loop.
Explanation:
In the uniform magnetic field suppose the rectangular wire loop of length L and width b is moved out with a uniform velocity v. suppose any instance x length of the loop is out of the magnetic field and L-x length is inside the loop.
Area of loop outside the field = b(L-x)
we know that flux φ= BA
B= magnitude of magnetic field , A= area
and emf [tex]\epsilon= \frac{d\phi}{dt}[/tex]
[tex]\epsilon=B\frac{dA}{dt}[/tex]
[tex]\epsilon=B\frac{db(L-x)}{dt}[/tex]
[tex]\epsilon=Bb\frac{d(L-x)}{dt}[/tex]
B,b and L are constant and dx/dt = v
⇒ε = -Bbv
which is a constant hence There is a constant emf induced in the loop.
