A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the student to overcome gravity is most nearly 1. P = 87.5 W. 2. P = 5, 600 W. 3. P = 1.1 W. 4. P = 875 W. 5. P = 560 W.

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29-11-2019
Physics

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A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the student to overcome gravity is most nearly 1. P = 87.5 W. 2. P = 5, 600 W. 3. P = 1.1 W. 4. P = 875 W. 5. P = 560 W.

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PhantomWisdom PhantomWisdom · Answer 1 · 2019-11-30T06:32:15+01:00

Answer:

Power, P = 560 W

Explanation:

Given that,

Weight of the student, F = 700 N

Distance, d = 8 m

Time taken, t = 10 s

To find,

The average power expended by the student.

Solution,

Let P is the power. The work done per unit time is called its power. It is given by :

[tex]P=\dfrac{W}{t}[/tex]

[tex]P=\dfrac{F\times d}{t}[/tex]

[tex]P=\dfrac{700\ N\times 8\ m}{10\ s}[/tex]

P = 560 W

So, the average power expended by the student to overcome gravity is most nearly 5670 watts.

nishantwork777 nishantwork777 · Answer 2 · 2021-11-16T07:10:04+01:00

The average power expended by the student to overcome gravity =

( 5.) P = 560 W

The formula for Power is given by the equation (1)

[tex]Power = \dfrac{Work}{Time}[/tex]...........(1)

Also the formula for Work is given by equation (2)

[tex]Work = Force \times Distance[/tex]............(2)

(Considering magnitude of Displacement)

From equation (1) and (2) we can get

[tex]Power = \dfrac{Force \times Distance}{Time}[/tex].......(3)

Also [tex]Speed= \dfrac{ Distance}{Time}[/tex]....(4)

From equation (2) , (3) and (4)

So [tex]Power= Force \times Speed[/tex]

Given

Weight of the Student = 700 N

Height of the rope = 8 m

Time taken to climb the rope = 10 s.

So from equation (3) we can get

Average Power expended by the student to overcome gravity = (700)[tex]\times[/tex] (8)/(10) = 560 W.

Hence option 5 is correct.

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