Answer:
The x-coordinate of point P is 6
Step-by-step explanation:
we have
A (2,3) and B (8,0)
we know that
Point P portions the segment AB in the ratio 2 to 1
so
[tex]AP=\frac{2}{3} AB[/tex]
and
[tex]AP_x=\frac{2}{3} AB_x[/tex]
where
AP_x represent the distance between the points A and P in the x-coordinates
AB_x represent the distance between the points A and B in the x-coordinates
[tex]AB_x=8-2=6\ units[/tex]
[tex]AP_x=\frac{2}{3} (6)=4\ units[/tex]
The x-coordinate of P is equal to
[tex]P_x=A_x+AP_x[/tex]
where
A_x represent the x-coordinate of A
substitute the values
[tex]P_x=2+4=6[/tex]
therefore
The x-coordinate of point P is 6
