Answer:
Only the daughters will be carriers and the probability is 1 or 100%
Explanation:
Homozygous dominant female = [tex]X^{G} X^{G}[/tex]
Affected male = [tex]X^{G}Y[/tex]
[tex]X^{G} X^{G}[/tex] x [tex]X^{G}Y[/tex]
Offspring = [tex]X^{G}X^{g}[/tex] (female), [tex]X^{G}X^{g}[/tex] (females), [tex]X^{G}Y[/tex] (male), [tex]X^{G}Y[/tex] (male)
For X-linked traits, male gender can either be affected or not affected, they cannot be carriers because the Y chromosome is hypothesized to not carry any gene. Since the two X chromosomes in female carry genes, they can be carriers for X-linked traits.
Considering the female children only, the probability is 1 or 100%.
