Two gears in a 3: 1 ratio gearset and with a diametral pitch of 4 are mounted at a center distance of 6 in. Find the number of teeth on the pinion. (please note that the smaller gear is the pinion, and the larger gear is the gear)

Respuesta :

Answer:

Number of teeth on pinion = [tex]N_{p}[/tex] = 12

Step-by-step explanation:

Given:

Gear ratio = 3 : 1 = 3

Diametral Pitch = P = 4

Center distance = c= 6 in

No. of teeth on Pinion = [tex]N_{p}[/tex] =?

Gear ratio =[tex]\frac{ Number. of. teeth. on. gear}{ Number. of. teeth. on. pinion}[/tex] = [tex]\frac{N_{g} }{N_{p}}[/tex] = 3

As Gear ratio = 3, so

Diameter ratio = [tex]\frac{d_{g} }{d_{p}}[/tex] = 3  

(Note : Diameter Ratio = Gear ratio )

[tex]d_{g} =3d_{p}[/tex]                                     Equation 1

Center Distance = c = [tex]\frac{d_{g} + d_{p}}{2}[/tex] = [tex]d_{g} + d_{p}[/tex]= 2 (c)

[tex]d_{g} + d_{p}[/tex] = 2 (6) = 12 in

substitute [tex]d_{g} [/tex] from equation 1, here

[tex]3d_{p} + d_{p}[/tex] = 12

[tex]4d_{p} [/tex] = 12

[tex]d_{p} [/tex] = [tex]\frac{12}{4}[/tex] = 3

[tex]d_{p} [/tex] =3in

Now : Diametral Pitch =P= [tex]\frac{N_{p} }{d_{p} }[/tex]

[tex]N_{p}[/tex] = [tex]d_{p}(P)[/tex]

[tex]N_{p}[/tex]  = 4 (3)

[tex]N_{p}[/tex] = 12

Which are the number of teeth on pinion