a carnot engine absorbs 200J of heat from a reservoir at the temperature of the normal boiling point of water and rejects heat to reservoir at the temperature of the triple point of water . find the heat rejected,the work done by the engine and the thermal efficiency.

The efficiency of the carnot engine, which is working between a hot source at a temperature [tex]T_{1}[/tex] and a cold source at a temperature [tex]T_{2}[/tex], is given by:

[tex]Efficiency=1-\frac{T_{2}}{T_{1}}[/tex]

The normal boiling point of water is 373 K. ([tex]T_{1}[/tex])

The temperature of triple point of water is 273.15 K ([tex]T_{2}[/tex])

[tex]Efficiency=1-\frac{273.15}{373}=0.27[/tex]

[tex]Efficiency=\frac{Work\:done}{Heat\:absorbed}=\frac{Work\:done}{200}=0.27\\Work\:done=0.27\times200=54J\\Work\:done=Heat\:absorbed-Heat\:rejected\\Heat\:rejected=Heat\:absorbed-Work\:done=200-54=146J[/tex]

a carnot engine absorbs 200J of heat from a reservoir at the temperature of the normal boiling point of water and rejects heat to reservoir at the temperature of the triple point of water . find the heat rejected,the work done by the engine and the thermal efficiency.​

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a carnot engine absorbs 200J of heat from a reservoir at the temperature of the normal boiling point of water and rejects heat to reservoir at the temperature of the triple point of water . find the heat rejected,the work done by the engine and the thermal efficiency.