Answer:
8 ft
Step-by-step explanation:
From the diagram in the file attached, we are drawing a line from the point F horizontally
Let the angle between the line FG and the horizontal line drawn be β
The point of intersection of the vertical line from G and the drawn horizontal line be A
The point of intersection of the vertical line from H and the drawn horizontal line be B
Distance between the points A and G be x ft
From the ΔFGA
tanβ = x ft÷12 inch
= x (∵ 1 ft = 12 inches)
From the ΔFHB
tanβ = 6 ft ÷ (12 inch + 2 ft)
= 2
By comparing the tanβ values obtained from both the triangles
x = 2 ft
∴ Height, in feet, of the beam that ends at point G = 6 + 2 =8 ft
