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A modified roulette wheel has 36 slots. One slot is​ 0, another is​ 00, and the others are numbered 1 through 34​, respectively. You are placing a bet that the outcome is an odd number.​ (In roulette, 0 and 00 are neither odd nor​ even.)

Respuesta :

Answer:0.472

Step-by-step explanation:

Given

there are 36 slots with 0 and 00 as two slots which are neither odd nor even

i.e. there are 34 remaining slots numbered 1 to 34

there are 17 odd terms and 17 even terms

thus Probability of getting a odd number is [tex]=\frac{17}{36}=0.472[/tex]

         

brownbagger111

Answer:

P(odd#'s) = number of odd numbers/total number of outcomes = 18/38 = 9/19

Step-by-step explanation:

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