Answer:
The percent of silver in the alloy is 81.87%.
Explanation:
Mass of the alloy = 0.1264 g
Mass of silver chloride precipitate = 0.1375 g
Moles of silver chloride precipitate =[tex]\frac{0.1375 g}{143.5 g/mol}=0.0009582 mol[/tex]
In 1 mole of silver chloride there are 1 mole of silver, then in 0.0009582 moles of silver chloride will ahve:
[tex]1\times 0.0009582 mol=0.0009582 mol[/tex] of silver
Mass of 0.0009582 moles of silver = 0.0009582 × 108 g/mol=0.1035 g
The percent of silver in the alloy:
[tex]\frac{\text{Mass of silver}}{\text{mass of an alloy}}\times 100[/tex]
[tex]=\frac{0.1035 g}{0.1264 g}\times 100=81.87\%[/tex]
