A diffraction grating that has 4500 lines/cm is illuminated by light that has a single wavelength. If a second order maximum is observed at an angle of 42° with respect to the central maximum, what is the wavelength of this light?

Respuesta :

Answer:

The wavelength is 742.7 nm.

Explanation:

Given that,

Grating = 4500 lines/cm

Angle = 42°

Order number =2

We need to calculate the distance

[tex]d=\dfrac{1\times10^{-2}}{4500}[/tex]

[tex]d=2.22\times10^{-6}\ m[/tex]

We need to calculate the wavelength

Using diffraction formula

[tex]d\sin\theta=m\times\lambda[/tex]

[tex]\lambda=\dfrac{d\sin\theta}{m}[/tex]

[tex]\lambda=\dfrac{2.22\times10^{-6}\times\sin42}{2}[/tex]

[tex]\lambda=7.427\times10^{-7}[/tex]

[tex]\lambda=742.7\ nm[/tex]

Hence, The wavelength is 742.7 nm.