Answer:21.3 m/s
Explanation:
Given
speed [tex]u=18.6 m/s[/tex]
mass of fish [tex]m_f=2.30 kg[/tex]
Altitude [tex]h=5.50 m[/tex]
Time taken to cover h
[tex]h=ut+\frac{at^2}{2}[/tex]
[tex]5.5=\frac{9.8\times t^2}{2}[/tex]
[tex]t^2=1.122[/tex]
[tex]t=1.05 s[/tex]
Vertical velocity after [tex]t=1.05 s[/tex]
[tex]v_y=0+gt[/tex]
[tex]v_y=9.8\times 1.05=10.38 m/s[/tex]
Horizontal velocity will remain same [tex]u=18.6 m/s[/tex]
Net velocity [tex]v_{net}=\sqrt{u^2+v_y^2}[/tex]
[tex]v_{net}=\sqrt{18.6^2+10.38^2}[/tex]
[tex]v_{net}=\sqrt{453.76}=21.30 m/s[/tex]
