Answer:
We failed to accept null hypothesis
Step-by-step explanation:
x= 5.74
Standard deviation = [tex]0.26[/tex]
[tex]H_0:\mu = 5.8\\H_a:\mu < 5.8[/tex]
n = 65
We will use z test
Formula : [tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
Substitute the values :
[tex]z=\frac{5.74-5.8}{\frac{0.26}{\sqrt{65}}}[/tex]
[tex]z=-1.86[/tex]
Refer the z table for p value
p value = 0.0314
α = 0.10
p value < α
So, we failed to accept null hypothesis
