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If you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode? If you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode?

A(aq)+1e−→A−(aq) at the cathode and B(aq)→B+(aq)+1e− at the anode.
A(aq)+1e−→A−(aq) at the anode and B(aq)→B+(aq)+1e− at the cathode

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dsdrajlin

Answer:

A(aq) + 1 e⁻ → A⁻(aq) at the cathode and B(aq) → B⁺(aq) + 1e⁻ at the anode.

Explanation:

In the anode occurs the oxidation, in which the reducing agent loses electrons, and its oxidation number increases.

B(aq) → B⁺(aq) + 1e⁻

In the cathode occurs the reduction, in which the oxidizing agent gains electrons, and its oxidation number decreases.

A(aq) + 1 e⁻ → A⁻(aq)

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