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If you are given an ideal gas with pressure (P) = 259,392.00 Pa and temperature (T) = 2.00 oC of 1 mole Argon gas in a volume of 8.8 dm3 , calculate R to the correct number of significant figures and units under given condition

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Answer:

R = 0.083 atm .L /  mol.K

Explanation:

Given data:

Pressure of gas = 259,392.00 Pa

Temperature = 2.0 °C

Moles = 1 mol

Volume = 8.8 dm³

R = ?

Solution:

First of all we will convert the units.

Pa to atm

259,392.00 /101325 = 2.56 atm

dm³ to L

8.8 dm³ = 8.8 L

2.0 °C to K

2+273 = 275 K

Now we will calculate the R:

PV = nRT

R = PV/ nT

R =  2.56 atm . 8.8 L / 1 mol. 275 K

R = 22.528  atm .L / 1 mol. 275 K

R = 0.083 atm .L /  mol.K

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