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Vertically polarized light with an intensity of 36.8 lux passes through a polarizer whose transmission axis is an angle of 51.0° with the vertical. What is the intensity and direction of transmitted light? If the second polarizer whose transmission axis is an angle of 88.0° with the vertical is placed after first polarizer, what is the intensity of transmitted light?

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Answer:

0.01774 lux

Explanation:

[tex]I_0[/tex] = Polarized light intensity = 36.8 lux

[tex]\theta[/tex] = Angle

Through first filter

[tex]I_1=I_0cos^2\theta\\\Rightarrow I_1=36.8cos^2{51}\\\Rightarrow I_1=14.57\ lux[/tex]

Through second filter

[tex]I_2=I_1cos^2\theta\\\Rightarrow I_2=14.57cos^2{88}\\\Rightarrow I_2=0.01774\ lux[/tex]

intensity of transmitted light is 0.01774 lux

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