Respuesta :
Answer:
T = 0.0266 N*m
Explanation:
we know that:
∑T = Iα
Where T is the torque, I is the moment of inertia and α is the angular aceleration.
first, we have to express in radians the angular velocity:
W = [tex]4*2\pi[/tex]
w = 25.132 m/s
with this result, the time t and using the next equation we can find the angular aceleration (α) as;
w = -αt
α = [tex]\frac{w}{t}[/tex]
α = -[tex]\frac{25.132}{52.2}[/tex]
α = -0.481 rad/[tex]s^2[/tex]
Also, we have to find the moment of inertia following the next equation:
I = [tex]\frac{1}{2}MR^2[/tex]
Where M is the mass and R is the radio of the wheel, so replacing the values, we get:
I = [tex]\frac{1}{2}(1.23)(0.3)^2[/tex]
I = 0.05535
now, we have to go back to the first equation ( ∑T = Iα) and replace the data as:
T = Iα
T = 0.05535(0.481)
T = 0.0266 N*m
