It is easy to find the equivalent mass for this compound
.
divide the molar mass of the compound by the valence of the element/ion.
Since, Sodium shows +1 oxidation state always
and it's 2 times. so the total charge is +2
so just divide the molar mass by 2
[tex] \text{Mass of } Na_2CO_3 = \frac{2\times \text{ mass of sodium } + \text{ Mass of Carbon } + 3\times \text{ mass of Oxygen} }{\text{total charge of Cation or Anion}} \\ \frac{2\times 23 + 12+3\times16}{2} \\ \frac{46+12+48}{2} \\ \frac{106}{2} \\ 53 [/tex]
