A stock solution contains a mixture of ~100 ppm chloride, fluoride, nitrite, bromide, nitrate and phosphate anions. In order to prepare 1 L of 100 ppm nitrite stock solution, you weigh out 150.0 mg of NaNO2. The actual concentration of nitrite would be:______.

Respuesta :

Answer:

[tex]150~ppm[/tex]

Explanation:

The first step is to draw the ionization reaction of [tex]NaNO_2[/tex], so:

[tex]NaNO_2~->~Na^+~+~NO_2^-[/tex]

The molar ratio between [tex]NaNO_2[/tex] and [tex]NO_2^-[/tex] is 1:1

The next step is the calculation of the concentration. We have to remember that the formula of ppm is:

[tex]ppm=\frac{mg}{L}[/tex]

In this case we will have a mass of 150 mg and a volume of 1 L so:

[tex]ppm=\frac{150~mg}{1~L}=~150ppm[/tex]