Answer:
We need to multiply 12 to each term to eliminate fractions.
Explanation:
Given expression:
[tex]6-\frac{3}{4}x+\frac{1}{3}=\frac{1}{2}x+5[/tex]
To eliminate the fraction we need to multiply each term by least common multiple of the denominators of the fraction.
The denominators in the above expressions are:
4, 3 and 2
The multiples of each can be listed below.
2⇒ 2,4,6,8,10,12,14,16.....
3⇒ 3,6,9,12,15,18
4⇒ 4,8,12.......
From the list of the multiples stated, we can see the least common multiple is 12.
So we will multiply each term by 12.
Multiplying 12 to both sides.
[tex]12(6-\frac{3}{4}x+\frac{1}{3})=12(\frac{1}{2}x+5)[/tex]
Using distribution,
[tex]72-9x+4=6x+60[/tex]
Thus we successfully eliminated the fractions.
