What equation is graphed in this figure?
y−4=−13(x+2)
y−3=13(x+1)
y+2=−3(x−1)
y−5=3(x−1)

y − 5 = 3(x − 1)
y = 0 => 0 - 5 = 3(x - 1)
- 5 = 3x - 3
- 5 + 3 = 3x
3x = - 2
x = - 2/3
x = - 0,6
x = 0
y - 5 = 3(0 - 1)
y = 5 - 3
y = 2