[tex]\frac{1}{2(y-3)}>\frac{1}{3(4-y)}=>3(4-y)>2(y-3)[/tex]
12 - 3y > 2y - 6
12 + 6 > 2y + 3y
18 > 5y
[tex]y<\frac{5}{18}[/tex]
y ∈ (-oo, [tex]\frac{5}{18}[/tex])