Answer:
Distance between the students is 2.4377 m
Explanation:
We have given that force between the students [tex]F=3.9\times 10^{-8}N[/tex]
Mass of first student [tex]m_1=56.5kg[/tex]
Mass of second student [tex]m_2=61.5kg[/tex]
Gravitational constant [tex]G=6.67\times 10^{-11}Nm^2/kg^2[/tex]
From gravitational law we know that force between two objects is given by
[tex]F=\frac{Gm_1m_2}{R^2}[/tex]
So [tex]3.9\times 10^{-8}=\frac{6.67\times 10^{-11}\times 56.5\times 61.5}{R^2}[/tex]
[tex]R=2.4377m[/tex]
So distance between the students is 2.4377 m
