Answer:
Acceleration of the object will be [tex]1.05m/sec^2[/tex]
Explanation:
We have given mass of the object m = 9 kg
spring constant k = 95 N/m
Spring is stretched by 10 cm
So x = 10 cm = 0.1 m
We know that force is given by [tex]F=kx=95\times 0.1=9.5N[/tex]
From newton's law we also know that force is given by
F = ma , here m is mass and a is acceleration
So [tex]9.5=9\times a[/tex]
[tex]a=1.05m/sec^2[/tex]