contestada

Water from a fire hose is directed horizontally against at a rate of 50.0 kg/s and a speed of 42.0 m/s.

What is the magnitude of the force exerted on the wall, assuming the water's horizontal momentum is reduced to zero?

Respuesta :

Answer:

Force, |F| = 2100 N

Explanation:

It is given that,

Water from a fire hose is directed horizontally against at a rate of 50.0 kg/s, [tex]\dfrac{m}{t}=50\ kg/s[/tex]

Initial speed, v = 42 m/s

The momentum is reduced to zero, final speed, v = 0

The relation between the force and the momentum is given by :

[tex]F=\dfrac{p}{t}[/tex]

[tex]F=\dfrac{mv}{t}[/tex]

[tex]F=50\ kg/s\times 42\ m/s[/tex]

|F| = 2100 N

So, the magnitude of the force exerted on the wall is 2100 N. Hence, this is the required solution.