Answer:
The number of students who have both car and bicycle = 234
Explanation:
We have given that 185 students have bicycle so [tex]n(A)=185[/tex]
And the students who have car are 68
So [tex]n(B)=68[/tex]
Students who have both car and bicycle [tex]n(A\cap B)=19[/tex]
From set theory we know that [tex]n(A\cup B)=n(A)+n(B)-n(A\cap B)[/tex]
[tex]n(A\cup B)=185+68-19=234[/tex]
So the number of students who have both car and bicycle = 234
