The car takes 3.15 s to stop
Explanation:
The motion of the car is a uniformly accelerated motion (=constant acceleration), therefore we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
Keeping in mind that
1 mile = 1609 metres
1 hour = 3600 seconds
Here we have:
[tex]u = 65 mph \cdot \frac{1609 m/mile}{3600 s/hour}=29.0 m/s[/tex] is the initial velocity, converted into m/s
v = 0 is the final velocity (the car comes to a stop)
[tex]a=-9.2 m/s^2[/tex] is the acceleration
And solving the equation for t, we find
[tex]t=\frac{v-u}{a}=\frac{0-29.0}{-9.2}=3.15 s[/tex]
Learn more about accelerated motion:
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