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A 47.0 kg uniform rod 4.25 m long is attached to a wall with a hinge at one end. The rod is held in a horizontal position by a wire attached to its other end. The wire makes an angle of 30.0 ∘ with the horizontal, and is bolted to the wall directly above the hinge.

If the wire can withstand a maximum tension of 1350 N before breaking, how far from the wall can a 69.0 kg person sit without breaking the wire?

Respuesta :

Manetho

Answer:

2.79 m

Explanation:

Use the static equilibrium condition, net torque actin on the system is zero.

[tex]\sum \tau= 0[/tex]

[tex]T(Lsin\theta)- Mg\frac{L}{2}-mgx=0[/tex]

solve for the distance of the person from the wall x

[tex]x= \frac{TLsin\theta-Mg(L/2)}{Mg}[/tex]

now putting the values we get

[tex]x= \frac{1350\times4.25sin30-47\times9.81\times(4.25/2)}{69\times9.80}[/tex]

= 2.79 m

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