Answer: False
Explanation:
Using the angular frequency formula derived from Hooke's law we have :
[tex]\omega =\sqrt{\frac{ k }{ m }} [/tex]
[tex]{\omega}^{ 2 }=\frac {k}{m}[/tex]
where k- is Hooke's constant
m- is mass attached to a spring
According to the formula the mass is inversely proportional to the square of the angular frequency angular which means that increasing the mass attached to the spring will decrease the angular frequency.
