Set up a linear equation(s) that will help you to find a solution to the following problem: One angle of a triangle is twice as large as another angle. The measure of the third angle is 20 more than the measure of the smallest angle. Find the measure of each angle of the triangle.
x+y+z=180 one is 2 times as another x=2y measure of 3rd angle (z) is 20 more than smalllest since y has to be doubled to get x, y is smallest z is 20 more than y z=20+y
we have x=2y z=20+y sub those x+y+z=180 2y+y+20+y=180 4y+20=180 minus 20 both sides 4y=160 divide 4 y=40 sub back x=2y x=2(40) x=80 z=20+y z=20+40 z=60
