Answer:
[tex]v = 15.45 m/s[/tex]
Explanation:
As per mechanical energy conservation we can say that here since friction is present in the barrel so we will have
Work done by friction force = Loss in mechanical energy
so we will have
[tex]W_f = (U_i + K_i) - (U_f + K_f)[/tex]
here we know that
[tex]W_f = F_f . d[/tex]
[tex]W_f = 40 \times 4[/tex]
[tex]W_f = 160 J[/tex]
Initial compression in the spring is given as
[tex]F = kx[/tex]
[tex]4400 = 1100 x[/tex]
[tex]x = 4 m[/tex]
now from above equation
[tex]W_f = (\frac{1}{2}kx^2 + 0) - (mgh + \frac{1}{2}mv^2)[/tex]
[tex]160 = (\frac{1}{2}1100(4^2) + 0) - (60 \times 9.8\times 2.50 + \frac{1}{2}(60)v^2)[/tex]
[tex]160 = 8800 - 1470 - 30 v^2[/tex]
[tex]v = 15.45 m/s[/tex]