Respuesta :
69. The student's skin was obviously warmer than the initial temperature of the bracelet. According to the second law of thermodynamics, heat transfers from a higher temperature to a lower temperature hence heat transfers from the student's skin to the bracelet warming up the bracelet.
70. moles of copper=mass of copper/molar mass of copper
=30.1g/(63.55g/mol)= 0.4736 moles Cu
71. Delta H( heat released) = mCp(deltaT) = 30.1g(0.385 J/gK)(33-19)K = 162.23J
72. Copper is chemically less active than iron.
70. moles of copper=mass of copper/molar mass of copper
=30.1g/(63.55g/mol)= 0.4736 moles Cu
71. Delta H( heat released) = mCp(deltaT) = 30.1g(0.385 J/gK)(33-19)K = 162.23J
72. Copper is chemically less active than iron.
69. The student's skin was obviously warmer than the initial temperature of the bracelet. According to the second law of thermodynamics, heat transfers from a higher temperature to a lower temperature. Hence, heat transfers from the student's skin to the bracelet warming up the bracelet.
70. To determine number of moles of copper:
Given mass=30.1 grams
Molar mass= 63.55 g/mol
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\ \text{Number of moles}=\frac{30.1}{63.55} =0.4736 \text { moles}[/tex]
Thus, the number of moles of copper is 0.4736.
71. Calculating the amount of heat released:
ΔH( heat released) = m Cp(ΔT)
= 30.1g(0.385 J/g. K)(33-19)K
ΔH= 162.23J
Thus, the amount of heat released is 162.23 J.
72. Copper is chemically less active than iron.
Copper does not displace iron from its solution since it is less reactive than iron. A more reactive metal displaces a less reactive metal from its solution.
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