For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have the following equation:
[tex]y = \frac {1} {2} x-7[/tex]
So:
[tex]m = \frac {1} {2}[/tex], the slope is positive
[tex]b = -7[/tex]
For the graph, we place the point on the coordinate axis:
[tex](x, y) :( 0, -7)\\(x, y) :( 1, - \frac {13} {2})[/tex]
We draw the line!
The graphic is attached.
ANswer:
[tex]m = \frac {1} {2}[/tex], the slope is positive
[tex]b = -7[/tex]
