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A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?
(1) 0.168 M (3) 0.620 M
(2) 0.480 M (4) 0.801 M

Respuesta :

Hagrid

Molarity is equal to the moles of solute over liters of solvent. In getting the molarity of HCl, you must know the formula for two solutions which is equal to M1V1 = M2V2.  (16.4 milliliters of HCl)M1 = (12.7 milliliters) (0.620 M KOH) and you have 0.480M HCl. The answer is number 2.

mahima6824soni

The molarity of the HCl acid is 0.480 M. The correct option is 2.

What is molarity?

Molarity is the division of the mass of the solution to the volume of the solution.

The formula that is used is

[tex]\rm M_1V_1= M_1V_2[/tex]

Putting the values in the equation

0.620 * 12.7 = M1 * 16.4 = 0.480

Thus, the molarity of the HCl acid is 2). 0.480 M.

Learn more about molarity

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