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Plane B is flying 55mph faster than Plane A and can fly 4275 miles in the same amount of time it takes Plane A to fly 4000 miles. Find the amount of time it takes for each plane to travel their respective distances.

Respuesta :

Answer: it takes 5s for each plane to travel their respective distances

Step-by-step explanation:

Let a = speed of plane A

Let b = speed of plane B

b = 55 + a

Time for plane A to fly 4000 miles

= 4000/a

Time for plane B to fly 4275 miles

= 4275/b

Since it takes same amount of time

4000/a = 4275/b

4000b = 4275a-------1

Put b = 55+a in eqn

4000(55+a) = 4275a

220000+4000a = 4275a

275a = 220000

a = 800

b = 55 +800 = 855

Time for plane A to fly 4000 miles

= 4000/800 = 5s

Time for plane B to fly 4275 miles

= 4275/855= 5s

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