Answer:
10 atm
Explanation:
Assuming the gas is kept at constant temperature, we can apply the following law (Boyle's law):
"For a gas kept at a constant temperature, the pressure of the gas is inversely proportional to its volume"
Mathematically,
[tex]pV=const.[/tex]
where p is the pressure of the gas and V its volume.
The equation can also be rewritten as
[tex]p_1 V_1 = p_2 V_2[/tex]
Where for the gas in the problem, we have:
[tex]p_1 = 2 atm[/tex] is the initial pressure
[tex]V_1 = 0.5 m^3[/tex] is the initial volume
[tex]p_2[/tex] is the final pressure
[tex]V_2 = 0.1 m^3[/tex] is the final volume
Solving for p2,
[tex]p_2 = \frac{p_1 V_1}{V_2}=\frac{(2)(0.5)}{0.1}=10 atm[/tex]
