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Solve the system of equations.
2x + 2y + 5z = 7
6x + 8y + 5z = 9
2x + 3y + 5z = 6
a. (x = 2, y = -1,2 - 1)
b. (x = 1, y = 0, z = 2)
c. (x = 3, y = -2, z = 0)
d. (x = 4, y = -3, z = 3)
Please select the best answer from the choices provided

Respuesta :

meredith48034

Answer:

using the first two equations cancelling the z

-2x-2y-5z=-7

6x+8y+5z=9

4x +6y= 2

using the second and the third equations cancelling the z

6x+8y+5z= 9

-2x-3y-5z= -6

4x +5y = 3

4x + 6y = 2

-4x -5y = -3

y= -1

2x + 2(-1) + 5z = 7

2x - 2 + 5z = 7

2x + 5z = 9

6x + 8(-1) + 5z = 9

6x - 8 + 5z = 9

6x + 5z = 17

-2x - 5z= -9

4x = 8

x = 2

2(2) + 2(-1) + 5z= 7

4 - 2 + 5z = 7

2 + 5z = 7

5z = 5

z = 1

(2, -1, 1)

the answer is a.

Step-by-step explanation:

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