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A rocket is launched straight up from the top of a 125-foot building with an initial velocity of 128 feet per second. Find the time interval when the rocket's height exceeds 317 feet.

Respuesta :

Rishi2005

Answer:

About 2.5 seconds

Step-by-step explanation:

317 divided by 128 equals 2.47, rounded off to 2 sig. figs. to 2.5

:)

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