Respuesta :

stevenslusser

Answer:

[tex]\overline{AB} \cong \overline{DE}[/tex]

Step-by-step explanation:

Under the AAS postulate, two triangles are congruent if any two angles and a non-included side are congruent in both. Therefore, if [tex]\angle{B} \cong \angle{E}[/tex] and [tex]\angle{C} \cong \angle{F}[/tex], then [tex]\overline{AB}[/tex] would need to be congruent to [tex]\overline{DE}[/tex] to prove that the two triangles are congruent. The other solution would be [tex]\overline{AC} \cong \overline{DF}[/tex], but that is not an answer choice.

Answer:

Third option

Step-by-step explanation:

Congruency by the AAS postulate

If 2 angles and a non- included side of one triangle are congruent to 2 angles and a non- included side of another triangle then the triangles are congruent.

Here ∠ABC ≅ ∠DEF and ∠ACB ≅ ∠DFE

The non- included side is AB ≅ DE

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