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31-10-2019
Mathematics

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What is the equation of a line that passes through the point (6, 1) and is perpendicular to the line whose equation is y=−2x−6 ?

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31-10-2019

Answer:

y=1/2x-2

Step-by-step explanation:

y=-2x-6

slope = -2x

reciprocal slope = I/2x

equation of line = y-y1=m(x-x1)

y-1=1/2(x-6)

y-1=1/2x-3

y=1/2x-2

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