A dinner order at a restaurant consists of a salad with dressing, an entrée, and three sides. The menu offers a salad with your choice of ranch, balsamic vinegar, or Italian dressing; a choice of entrée from catfish, roast beef, meat loaf, or pork chops; and, as sides, fried okra, corn, black-eyed peas, French fries, rice, mashed potatoes, pinto beans, green beans, or squash. How many possible dinner orders are available at the restaurant

Respuesta :

Answer:

Imma try my best :)

ranch choices:

balsamic, vinegar, or Italian dressing

= 3

choice of entrée:

catfish, roast beef, meat loaf, or pork chops

= 4

Choices for sides

fried okra, corn, black-eyed peas, French fries, rice, mashed potatoes, pinto beans, green beans, or squash.

=9

Add all of the numbers together: 3 + 4 + 9 = 16

= 16 is the amount of choices, Take the amount of total choices and options in general (entrée,side,ranch) and divide.

= 5.33

(sorry if this answer s incorrect, This is a lot of words to take in)

The number of possible diner orders that are available at the restaurant is; 403200

What is the number of possible combination?

We are told that there are;

4 kinds of dressing from ranch, balsamic vinegar, or Italian dressing.

4 entrees from catfish, roast beef, meat loaf, or pork chops

10 sides from fried okra, corn, black-eyed peas, French fries, rice, mashed potatoes, pinto beans, green beans, or squash.

Out of these given we can only pick 3 sides.

Thus, the number of possible dinner orders available at the restaurant are; 4 * 4 x 10!/(3! * 4!) = 403200

Read more about Combination probability at; https://brainly.com/question/11732255