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An Atwood's machine consists of a 1.060 kg mass and a 1.000 kg mass connected by a string over a massless and frictionless pulley. Suppose that the system has a frictional force of 0.056N. Determine the acceleration of the system in m/s^2. Assume that g is 9.80 m/s^2.

Respuesta :

Answer:

a= 0.264 m/s²

Explanation:

Given that

m₁= 1.06 kg

m₂=1 kg

Fr = 0.056 N

Mass first will move downwards and mass second will move upward.

Lets take acceleration of system is a.

From Newtons law

( m₁ - m₂ ) g - fr = (m₁+m₂) a

Now by  putting the values

(1.06 - 1) x 10 - 0.056 = (1.06+1) a                ( taken g= 10 m/s²)

0.6 - 0.056 = 2.06 a

a= 0.264 m/s²

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