Answer:
x1=1,5
x2=-3
(2x-3)(x+3)=0
Step-by-step explanation:
First we have to leave the equation of the parabola equalized ro 0:
[tex]2x^2+ 5x - 9 = 2x.\\2x^2+5x-2x-9=0\\2x^2+3x-9=0[/tex]
We know have to search for two pairs of numbers the first one that multiplied give as result 2 and the second one has to be -9, then with a cross multiplication they will have to give as a resutl +5:
Pairs to +2:
2*1
1*2
Pairs to -9:
-3*3
3*-3
9*-1
-9*1
We will use 2*1 and -3*3:
(2x-3)(x+3)=0
SO that would be the answer for the roots of the parabola:
2x-3=0
x=3/2
x+3=0
x=-3
