Answer:
[tex]\textbf{$g(f(x)) = \frac{2x + 1}{2}$ }\\[/tex]
Step-by-step explanation:
[tex]$ f(x) = x - 3 $$ g(x) = x + \frac{7}{2} $\textup{To compute g(f(x))}$ \implies g(f(x)) = g(x - 3) $\\\textup{i.e., to substitute $x - 3$ instead of x in g(x)}\\$ \therefore g(x - 3) = x - 3 + \frac{7}{2} $ \\\textup{Simplifying this we get:}\\\textbf{$g(f(x)) = \frac{2x + 1}{2}$}[/tex]