52 g of hydrogen H₂
Explanation:
I will assume that the problem is talking about the hydrogenation of carbon dioxide CO₂ not carbon monoxide CO. It is harder to reduce carbon dioxide than carbon monoxide and if you manage to reduce carbon dioxide you can reduce the carbon monoxide as well.
This reaction it will take place in the presence of catalyst at a specific temperature and pressure.
CO₂ + 4 H₂ → CH₄ + 2 H₂O
Now taking into the account the chemical reaction we devise the following reasoning:
if 1 mole of CO₂ react with 4 moles of H₂
then 6.5 moles of CO₂ react with X moles of H₂
X = (6.5 × 4) / 1 = 26 moles of H₂
number of moles = mass / molecular wight
mass = number of moles × molecular wight
mass of H₂ = 26 × 2 = 52 g
Learn more about:
hydrogenation reaction
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