The effectiveness of a television commercial depends on how many times a viewer watches it. After some experiments an advertising agency found that if the effectiveness E is measured on a scale of 0 to 10, then E(n) = 2 3 n − 1 84 n2 where n is the number of times a viewer watches a given commercial. For a commercial to have maximum effectiveness, how many times should a viewer watch it?

Respuesta :

Answer:

n =28

Step-by-step explanation:

Given that

E(n) = 2n/ 3 -n²/84

measured on a scale of 0 to 10

The maximum vale of E is occurs  when

dE/dn = 0

E(n) = 2n/ 3 -n²/84

dE/dn = 2/ 3 -2n/84

For maximum

2/ 3 -2/84 n = 0

84  = 3 n

n =28