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Sergei tees off on a stationary hockey puck using his most powerful slap shot. If he can exert a force of 250 N on the 500 gram puck for a time of 0.1 seconds, what velocity will he give to it, and how far will the puck move in the time it is on his stick?

Respuesta :

Answer: velocity = 50m/s

Distance moved=5m

Explanation:

Using the formula Ft=Mv i.e impulse= momentum

Where F= force ,t= time, M= mass, v = velocity

In this case we need to find v,

F,t,M are all given in the question.

Therefore, substituting the values we have

250N×0.1s=0.5kg×v. Mass=500g= 0.5kg

v=25/0.5= 50m/s

The distance the puck will move when it is on his stick.

D= Velocity × time

D=50m/s × 0.1s

D=5m

Goodluck...

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