Answer:
[tex]\dot{Q_{out}} = 874.96 KW[/tex]
Explanation:
given,
steam turbine operates at P₁ = 1.6 MPa
steam inlet temperature T₁= 350°C
saturation vapor T₂= 30°C
the enthalpies (h₁) = 3146 kJ/kg
h₂ = 2555.6 kJ/kg
assuming no change in internal energy
[tex]\dot{E_{in}} = \dot{E_{out}}[/tex]
[tex]\dot{m_1}h_1 = \dot{m_2}h_2 + \dot{w_{out}}+\dot{Q_{out}}[/tex]
[tex]\dot{Q_{out}} = \dot{m}(h_1-h_2)-\dot{W_{out}}[/tex]
[tex]\dot{Q_{out}} = 22.4\times (3146-2555.6)-12,350[/tex]
[tex]\dot{Q_{out}} = 874.96 KW[/tex]
