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Benzene is a carcinogenic (cancer-causing) compound. A benzene-contaminated water sample contains 5.9×10−5 % benzene by mass. Part A What volume of the water in liters contains 235 mg of benzene? (Assume that the density of the solution is 1.0 g/mL.)

Respuesta :

Answer:

398.3 L

Explanation:

Percent composition is percentage by the mass of element present in the compound.

Given that the benzene is [tex]5.9\times 10^{-5}[/tex] % by mass.

It means that [tex]5.9\times 10^{-5}\ g[/tex] of benzene is present in 100 g of the total sample

Also, Given that : Mass of benzene = 235 mg = 0.235 g ( 1 mg = 0.001 g)

Mass % = [tex]\frac{Mass_{Benzene}}{Mass\ of\ the\ sample}\times 100[/tex]

Thus,

Mass of the sample = [tex]\frac{0.235\times 100}{5.9\times 10^{-5}}[/tex] = 398305.08474 g

Mass of benzene = 0.235 g

Thus, Mass of water = 398304.85 g

Density = 1 g/mL

So, Volume = 398304.85 mL = 398.3 L ( 1 mL = 0.001 L)

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