Answer:0.61 m
Explanation:
Given
Initial velocity (u)=7.40 m/s
launch angle [tex]\theta =45^{\circ}[/tex]
height of fence=0.7 m
Trajectory of Projectile is given by
[tex]y=x\tan \theta -\frac{gx^2}{2u^2\cos^2\theta }[/tex]
For x=2.1 m
[tex]y=2.1\tan (45)-\frac{9.8\times 2.1^2}{2\times 7.4^2\times (\cos 45)^2}[/tex]
[tex]y=2.1-0.789[/tex]
[tex]y=1.31 m[/tex]
At x=2.1 m Y=1.31
therefore Fox clear fence by a margin =1.31-0.7=0.61 m
